For the following reaction 2MnO4- 5H2C2O4 +6H+ =2Mn+ +8H2O +10CO2 E(MnO4-/Mn2+)=+1.51V amp;E(CO2/H2C2O4)=-0.. For the following reaction=2Mn+ +8H2O +10CO2E(MnO4-/Mn2+)=+1.51V &E(CO2/H2C2O4)=-0.49V.At 298K, the equilibrium constant is
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For the following reaction 2MnO4- 5H2C2O4 +6H+ =2Mn+ +8H2O +10CO2 E(MnO4-/Mn2+)=+1.51V amp;E(CO2/H2C2O4)=-0.
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